Physics: The displacement x of a simple harmonic motion is given by X = 24 cos (6.28t + 1.57) meters. What is the maximum speed of the oscillator.

The displacement x of a simple harmonic motion

bananaslugs

30.01.2022

X(t)= 24 cos (6.28 t +1.57)

And for this case we can write this expression like this:

$X(t) =A cos (wt +\phi)$

The velocity would be given by the first derivate and we got:

$V(t) = -wA sin (wt +\phi)$

And the maximum velocity would be:

$V_{max}= |6.28 *24| = 150.72 m/s$

Explanation:

For this case we have the following function for the position:

X(t)= 24 cos (6.28 t +1.57)

And for this case we can write this expression like this:

$X(t) =A cos (wt +\phi)$

The velocity would be given by the first derivate and we got:

$V(t) = -wA sin (wt +\phi)$

And the maximum velocity would be:

$V_{max}= |6.28 *24 |= 150.72 m/s$

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strawberrymrmr756

17.10.2021

Cutting, shaping, and fastening wood.

Installing rafters, joists, windows, and subflooring.

Setting hardwood floors.

Building kitchen cabinets.

Explanation:

Got the answer wrong so I could give you the right one :,)

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