The horizontal surface on which the block of mass 5.4kg slides is frictionless. The force of 57N acts on the blockin a horizontal direction and the force of 171N acts on the block at an angle as shown below. What is the magnitude of the resulting acceleration of the block?
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Ответ:
Explanation:
F ncnfnngn
Ответ:
E(p) = mgh
(Mass x gravity x height)
Therefore energy = (5.3)(9.8)(6.6)
= 342.8 J
How did I get 9.8?
9.8 is the constant for gravity