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chaparro0512
16.12.2019 •
Physics
The mass of a stroller and the child it carries is 21.1 kg. a woman pushes the stroller with a force of 121 n at an angle of 41.0° to the vertical. the stroller experiences a friction force of 4.0 n. what is the stroller's acceleration forward?
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Ответ:
Explanation:
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
We define the x-axis in the direction parallel to the movement of the stroller and the y-axis in the direction perpendicular to it.
Forces acting on the stroller
W: Weight of the stroller and the child : In y-direction downward
FN : Normal force : In y-direction upward
f = 4 N: Friction force: In x-direction opposite to the movement
P = 121 N Woman's force on the stroller, at an angle of 41.0° to the y-axis
x-y components of the F
Px= 121 N*sin41° = 79.38 N
Py= 121 N*cos41° =91.32 N
Stroller's acceleration forward
We apply the formula (1)
∑Fx = m*a
Px - f = m*a
79.38 - 4 = (21.1 )*a
75.38 = (21.1 )*a
a = 75.38 / (21.1 )
a = 3.57 m/s²
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Ответ:
broo what's the question?
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