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castroarlety
17.01.2021 •
Physics
The planet Venus has a mass of 4.87 x 10^24 kg and a radius of 6.05 x 10^6 km. What is
the magnitude of the gravitational force that an 81-kg person would experience while
standing on the surface of Venus?
(A) 179 N
(B) 719 N
(C) 259 N
(D) 7.19 x 10^8N
(E) 4.19 x 10^9N
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Ответ:
The gravitational force that an 81-kg person would experience while standing on the surface of Venus is approximately;
(A) 719 N
Explanation:
The question relates to gravity calculation for which we use the Newton's gravitational law which is presented as follows;
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³kg⁻¹s⁻²
F = The gravitational force between the two masses, "M" and "m"
r = The distance between the centers of the two masses
M = The mass of one body interacting in the gravitational force
m = The mass of the other body interacting in the gravitational force
The given parameters are;
The mass of Venus, M = 4.87 × 10²⁴ kg
The radius of the planet Venus, r (is corrected) = 6.05 × 10³ km = 6.05 × 10⁶ km
The mass of the person standing on the surface of Venus, m = 81-kg
Therefore, by plugging in the values, we get;
From Newton's third law of motion, the gravitational force that the 81-kg person experiences while standing on the surface of Venus = F ≈ 719 N.
Ответ:
38 m/s north
Explanation: