Physics: Two narrow parallel slits (separated by the distance d = 0.9 mm) are illuminated by monochromatic light with lambda = 550 nm. The two slits create a diffraction pattern of bright and dark spots. Find the smallest angle theta1 (in degrees) at which the rays from the two slits create a bright spot.

Two narrow parallel slits (separated by the distance

angelvega2003

23.01.2022

The smallest angle is $\theta = 0.00061^o$

Explanation:

From the question we are told that

The distance of separation is d = 0.9 mm

The wavelength is $\lambda = 550nm$

General the location of the interference fringes is mathematically represented by

$dsin \theta = m \lambda$

m is the order of the fringe

Now the smallest angle at which both ray create a bright spot would be when

m= 1

$dsin \theta = \lambda$

$sin \theta =\frac{\lambda}{d}$

$\theta = sin ^{-1} (\frac{\lambda}{d} )$

Substituting values

$\theta = sin ^{-1}(\frac{550*10^{-9}}{0.9*10^{-3}} )$

$= sin^{-1}(0.0006111)$

$\theta = 0.00061^o$

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kdtd3163

24.12.2021

the collision is elastic as the carts rebound off each other.

by conservation of momentum, the small mass will have a larger change in velocity.

so the ans is The small cart changes its velocity the most.

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