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jameanch7182
05.05.2020 •
Physics
What are the signs of δs univ, δs surr, and δs sys, respectively, for water freezing at −10°c?
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Ответ:
Explanation:
δs sys = change in entropy of the system
= dQ / T
dQ is heat exchanged . It is negative as heat is given out and T = 273 k so
δs sys = - dQ / T
Its sign will be negative.
δs surr = dQ / T₁ , dQ is heat given by the water to freeze . It is positive
δs surr = + dQ / T₁ , T₁ is temperature of the surrounding
Sign of δs surr is positive .
δs univ = δs sys + δs surr
- dQ / T + dQ / T₁
T < T₁
dQ / T >dQ / T₁
- dQ / T + dQ / T₁ will be negative
δs univ will be negative .
Ответ:
1.) A
2.) B
3.) B
4.) A
5.) A
6.) C
7.) B
Explanation: