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uehlingt39
06.12.2019 •
Physics
What energy change is associated with the reaction to obtain one mole of h2 from one mole of water vapor? the balanced equation is 2 h2o(g) ® 2h2(g) + o2(g) and the relevant bond energies are: h — h = 436 kj/mol; h — o = 467 kj/mol; o — o = 146 kj/mol; o o = 498 kj/mol.
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Ответ:
ΔH = 249 kJ/mol
Explanation:
The balanced reaction is:
2H₂O(g) → 2H₂(g) + O₂(g) (1)
To calculate the energy change to obtain one mole of H₂(g) from one mole of H₂O(g), the coefficients of the reaction (1) must be halved:
H₂O(g) → H₂(g) + 1/2O₂(g) (2)
The enthalpy of the reaction (2) is given by:
Where
: is the bond enthalpy of reactants and
: is the bond enthalpy of products.
For the reactants we have the next bond energies:
2 x (H-O) = 2 x (467)
And the bond energies for the products are:
H-H + (1/2) (O=O) = 436 + (1/2)(498)
So, the enthalpy of the reaction (2) is:
I hope it helps you!
Ответ:
the answer is c
Explanation:
this is a weird question