What is the displacement after 6 seconds when a car is moving at 12m/s and coasts up a hill with a uniform aacceleration of -1.6 m/s^2

The kinematic formula using displacement, time, initial velocity, and acceleration:
x = v t+.5 a t^2
x= (12m/s)(6s) + .5(-1.6m/s^2)(6s)^2
x= 72m - 28.8m
x = 43.2 m

There's no statements to choose from that I can see. But, it looks like the question is about magnetic fields, such as that surrounding a magnetised ferromagnetic iron object. Overall, in such fields, the field lines are formed into closed loops (think of the magnetic field around a wire carrying an electric current - closed circular loops with the wire at the centre). This is in distinction to the case of an electrostatic field, and a gravitational field.