ShadowShu8658
01.02.2020 •
Physics
What is the electric force acting between two charges of 0.0042 c and −0.0050 c that are 0.0030 m apart?
a. −2.1 1010 n
b. 2.1 1010 n
c. 6.3 107 n
d. −6.3 107 n
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Ответ:
A.−2.1 × 10^10 N
Explanation:
Using the formula;
E = k Q1Q2/d²
Where;
E is the electrical force
k is the constant
Q1, Q2 are the two charges and
d is the distance between the two charges
Therefore;
E = (9 x 10^9) × (0.0042) × (-0.0050) / (0.0030)²
= -2.1 x 10^10 N
Therefore; electrical force acting between the two charges is -2.1 x 10^10 N.
Ответ: