What is the power dissipated by the parallel resistor circuit shown above?
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Ответ:
P = (voltage squared)/(resistance).
Resistance of 3 equal resistors in parallel is 1/3 of the value = 100/3 ohms.
Power = (40^2)/ (100/3)
. = (1600 • 3) / (100)
. =. 48 watts .
Ответ:
The right answer is "131812.5".
Explanation:
The given values are:
Mass,
m = 15 kg
Velocity,
v = 45 m/s
As we know,
⇒![PE_1=mgh](/tpl/images/1326/5950/ae672.png)
On putting the values, we get
⇒![=15\times 9.8\times 1000](/tpl/images/1326/5950/1fe1a.png)
⇒![=147000 \ J](/tpl/images/1326/5950/170e2.png)
According to the question,
⇒![KE_f=\frac{1}{2}\times 15\times 45^2](/tpl/images/1326/5950/bd5cb.png)
⇒![=\frac{1}{2}\times 15\times 2025](/tpl/images/1326/5950/1a10d.png)
⇒
hence,
⇒![PE_i=KE_f+W_{air}](/tpl/images/1326/5950/37568.png)
or,
⇒![W_{air} = PE_i-KE_f](/tpl/images/1326/5950/ebfe4.png)
⇒![=147000-15137.5](/tpl/images/1326/5950/de517.png)
⇒![=131812.5 \ J](/tpl/images/1326/5950/d144f.png)