Physics: What minimum separation between two parallel plates of glass (nglass =1.5) produces constructive interference for the reflected light with a 710 nm wavelength if the gap between the plates is filled with oil with noil =1.8?

I need answers so sorry guys just givin fake answers noefje...

What minimum separation between two parallel plates

twhalon72

31.01.2022

The value is $t = 9.861 *10^{-8} \ m$

Explanation:

From the question we are told that

The refractive index of glass is $n_{glass} = 1.5$

The wavelength is $\lambda = 710 nm = \frac{710}{1 * 10^9} = 710*10^{-9} \ m$

The refractive index of oil is $n_{oil} = 1.8$

Generally the condition for refractive index is mathematically represented as

$2 * t = [m + \frac{1}{2} ] \frac{\lambda}{n_{oil}}$

Where t is the separation between two parallel plates of glass , now at minimum m which is the order of maxima produced is = 0

$2 * t = [0 + \frac{1}{2} ] \frac{710 *10^{-9}}{1.8}$

$t = 9.861 *10^{-8} \ m$

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