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lauren21bunch
21.11.2019 •
Physics
When the current in a toroidal solenoid is changing at a rate of 0050 n5, the magnitude of the induced emf is 126 mv,when tire current equals 1.40 a, the average flux through each turn of the solenoid is 000285 wb. how many turns doesthe solenoid have?
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Ответ:
N = 1238
Explanation:
It is given that,
Change in current in the toroidal solenoid,![\dfrac{dI}{dt}=0.05\ A/s](/tpl/images/0384/0575/a1fdd.png)
Induced emf in the solenoid,![\epsilon=126\ mV=126\times 10^{-3}\ V](/tpl/images/0384/0575/0522a.png)
Current in tire, I = 1.4 A
Flux in the solenoid,![\phi=0.00285\ Wb](/tpl/images/0384/0575/737fa.png)
The induced emf in the solenoid is given by :
L is the self inductance of the solenoid
The self inductance of solenoid is given by :
From equation (1) and (2) :
N = 1237.89
or
N = 1238
So, the number of turns in the solenoid is 1238. Hence, this is the required solution.
Ответ:
sure
Explanation: