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elizabethhubbe
06.01.2020 •
Biology
Consider a cross between individuals that are: aabbccdd and aabbccdd in which all genes segregate independently. what frequency of progeny will have the same genotype as the aabbccdd parent?
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Ответ:
1/16
Explanation:
The genotype of parents: AaBbCcDd and AAbbccDD
To calculate the frequency of a child with a specific genotype, we can calculate the individual frequencies for each gene and apply the product rule to calculate the overall frequency.
Aa x AA = 1/2 Aa: 1/2 AA
Bb x bb = 1/2 Bb: 1/2 bb
Cc x cc = 1/2 Cc: 1/2 cc
Dd x DD= 1/2 DD: 1/2 Dd
Therefore, the frequency of a progeny with genotype AAbbccDD = 1/2 AA x 1/2 bb x 1/2 cc x 1/2 DD = 1/2 x 1/2 x 1/2 x 1/2 = 1/16 or 0.0625 .
Ответ:
kk I will.
when I'll go n the web
Explanation
have a nice day!