Chemistry: 3. Describe the process behind how students recover an individual s remains from a surface grave.

3. Describe the process behind how students recover

Ответ:

4300252063

20.04.2021

By using the techniques of archeology.

Explanation:

Students recover an individual's remains from a surface grave by using the techniques of archeology field to scrape away the layers of soil from that remains in a way that the remains can't be damaged. If they find the remains within 10 centimeters of digging, they can dig down further in order to dig out all the remains safely. The instruments of archeology field are used because they are light and can be used to dig out fossils of ancient organisms.

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Ответ:

rodrickahammonds

01.08.2020

Chemistry

D) Methane CH4

Explanation:

Hello,

In this case, among the options, assuming for all the fuels a mass of 100 g, the combustion reaction reaction and stoichiometry for carbon dioxide is shown below:

A) Benzene C6H6

$C_6H_6+\frac{15}{2} O_2\rightarrow 6CO_2+3H_2O$

$m_{CO_2}=100gC_6H_6*\frac{1molC_6H_6}{78gC_6H_6}*\frac{6molCO_2}{1molC_6H_6} *\frac{44gCO_2}{1molCO_2} =347.4gCO_2$

B) Cyclohexane C6H12

$C_6H_{12}+9 O_2\rightarrow 6CO_2+6H_2O$

$m_{CO_2}=100gC_6H_{12}*\frac{1molC_6H_{12}}{84gC_6H_{12}}*\frac{6molCO_2}{1molC_6H_{12}} *\frac{44gCO_2}{1molCO_2} =314.3gCO_2$

C) Glucose C6H12O6

$C_6H_{12}O_6+6 O_2\rightarrow 6CO_2+6H_2O$

$m_{CO_2}=100gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6} *\frac{44gCO_2}{1molCO_2} =146.7gCO_2$

D) Methane CH4

$CH_4+2O_2\rightarrow CO_2+2H_2O$

$m_{CO_2}=100gCH_4*\frac{1molCH_4}{16gCH_4}*\frac{6molCO_2}{1molC_6H_{12}} *\frac{44gCO_2}{1molCO_2} =1650gCO_2$

Therefore, for equal masses D) Methane CH4 yield the greatest mass of carbon dioxide.

Regards.

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3. Describe the process behind how students recover an individual's remains from a surface grave.

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