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dinapaul424
18.12.2019 •
Chemistry
Ch3ch2ch2cl exhibits hydrogen bonding\rm ch_3ch_2ch_2cl exhibits blank, which are stronger than blank, so it has a higher boiling point than \rm ch_4 and \rm ch_3ch_2ch_3., which are stronger than dipole-dipole forces\rm ch_3ch_2ch_2cl exhibits blank, which are stronger than blank, so it has a higher boiling point than \rm ch_4 and \rm ch_3ch_2ch_3., so it has a higher boiling point than ch4 and ch3ch2ch3.
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Ответ:
1-chloropropane exhibits dipole-dipole forces which are stronger than London dispersion forces, so it has a higher boiling point than methane and propane
Explanation:
Both methane and propane are non-polar molecules in contrast to 1-chloropropane. This means the only predominant forces in the two molecules are London dispersion forces occurring due to bonded electron interactions. They are much weaker than the actual dipoles formed by a presence of an electronegative atom having lone pairs on it.
Ответ:
Aurangzeb fought many wars of expansion (not all of them successful).He fought with Jatts,Suni-muslims,nawab of bengal and other rulers. These wars had cost a lot of money, and the biggest war was fought with Marathas which war was considered as a no result war.This war was continued for 25 years because Marathas were located in remote areas(high peaks) and when Aurangzeb was capturing one post of Marathas and move forward to another post,previous one was recaptured by Marathas again.This war was without any conclusion and Aurangzeb spent alot of money in this war.At last his money balance was as like as common man.
Secondly, Aurangzeb started putting taxes on non-Muslims which were called Jaziya tax and these taxes were end up at Akbar's ruling.This caused hardships and famine for the ordinary Indian.About 70% of population was of Hindus in subcontinent at that time. All hindu groups declared Aurangzeb as a unpopular and unsuccessful ruler.
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