If a sample of carbon monoxide is at 57 degreees celsius and under 67.88 kpa of pressure and takes up 85.3 l of space how many moles of carbon dioxide are present in the sample?

57 degrees celcius is equal to 330 degrees kelvin
67.88 kPa is equal to 67880 Pa
85.3 liters is equal to 0.0853 m^3

Now, the equation we will use to solve this question is:
PV = nRT where:
P is the pressure of gas = 67880 Pa
V is the volume of gas = 0.0853 m^3
n is the number of moles we are looking for
R is the gas constant = 8.31441 J K-1 mol-1
T is the temperature of gas = 330 degrees kelvin

Substitute with the givens in the above equation to get n as follows:
n = (PV) / (RT)
n = (67880*0.0853) / (8.31441*330)
n = 2.11 moles

Mass % of hydrogen = 20.9 %

Explanation:

Given data:

Mass of hydrogen = 0.485 g

Mass of water = 2.32 g

Mass percent of hydrogen = ?

Solution:

Mass % of hydrogen = mass of hydrogen / mass of water × 100

Mass % of hydrogen = 0.485 g/ 2.32 g × 100

Mass % of hydrogen = 0.209  × 100

Mass % of hydrogen = 20.9 %

HOPE IT HELPS