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ayoismeisjjjjuan
06.01.2022 •
Chemistry
PLEASE HELP ASAP WILL GIVE BRAINLIEST
(dont give chegg link pls)
How much heat is required to convert 150 g of liquid H2O at 43.5 °C into steam at 130 °C?
Specific heat of liquid water is 4.18 J/g oC.
Specific heat of water vapor is 1.84 J/g oC.
ΔHvap = 40.67 kJ/mol
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Ответ:
The amount of heat required to convert H₂O to steam is : 382.62 kJ
Given data :
Mass of liquid water ( m ) = 150 g
Temperature of liquid water = 43.5°C
Temperature of steam = 130°C
Determine the amount of heat requiredThe amount of heat required = ∑ q1 + q2 + q3 ----- ( 1 )
where ;
q1 = heat required to change Temperature of water from 43.5°C to 100°C . q2 = heat required to change liquid water at 100°C to steam at 100°C
q3 = heat required to change temperature of steam at 100°C to 130°C
For q1M* S
*ΔT
= 150 * 4.18 * ( 100 - 43.5 )
= 35425.5 J
For q2moles * ΔHvap
= (150 / 18 )* 40.67 * 1000
= 338916.67 J
For q3M * S
* ΔT
= 150 * 1.84 * ( 130 -100 )
= 8280 J
Back to equation ( 1 )
Amount of heat required = 35425.5 + 338916.67 + 8280 = 382622.17 J
≈ 382.62 kJ
Hence we can conclude that The amount of heat required to convert H₂O to steam is : 382.62 kJ.
Learn more about Specific heat of water :
Ответ:
Sorry don’t know
Explanation: