Suppose two chemical reactions are linked together in a way that the O2 produced inthe first reaction goes on to react completely with Mg to form MgO in the second reaction.Reaction one: 2 KClO3 3 O2→ + 2 KClReaction two: 2 Mg + O2 2 MgO→If you start with 4 moles of KClO3, how many moles of MgO could eventually form?
A) 2 moles
B) 4 moles
C) 6 moles
D) 12 moles
E) none of the above
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Ответ:
12 moles of MgO could eventually form.
Explanation:
In the reaction:
2KClO₃ → 3O₂ + 2KCl
2 moles of KClO₃ produce 3 moles of O₂. 4 moles of KClO₃ produce:
4 mol KClO₃ × (3 mol O₂ / 2 mol KClO₃) = 6 mol O₂
In the second reaction:
2Mg + O₂ → 2MgO
1 mole of O₂ produce 2 moles of MgO. Thus, 6 mol of O₂ produce:
6 mol O₂ × (2 mol MgO / 1 mol O₂) = 12mol MgO
Thus, 12 moles of MgO could eventually form.
Ответ:
i think option d