What are the answers??

The percent composition :

Al : 15.79%

S : 28.07%

O : 56.14%

Given

Aluminum, Oxygen, and Sulfur in Al₂(SO₄)₃ compound

Required

The percent composition

Solution

Molar mass of Al : 27 g/mol

Molar mass of O : 16 g/mol

Molar mass of S : 32 g/mol

Molar mass of Al₂(SO₄)₃ : 342 g/mol

% Al = 2.MM Al / MM Al₂(SO₄)₃ x 100%=2.27/342 x 100%=15.79%

% S = 3. MM S / MM Al₂(SO₄)₃ x 100%= 3.32/342 x 100%=28.07%

% O = 12.MM O / MM Al₂(SO₄)₃ x 100%= 12.16/342 x 100%=56.14%

No because of the equation Hydrogen is brought out of it. This will make the equation uneven therefor it is invalid.

Explanation: