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30.10.2020 •
Mathematics
A particle moves along the x-axis so that at any time t≥0 its position is given by x(t)=12(a−t)2, where a is a positive constant. For what values of t is the particle moving to the right?
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Ответ:
For the particle to move to the right, 0 ≤ t ≤ a
Step-by-step explanation:
The particle under motion on the x-axis given by the equation x(t) = 12(a−t)² for t ≥ 0, where a is a positive constant.
To find the values of t for which the particle is moving to the right, this implies that the particle must move along the positive x-axis. This implies that x(t) ≥ 0.
So, to find the value of t for which the particle moves to the right, we solve the inequality x(t) ≥ 0 ⇒ 12(a−t)² ≥ 0
12(a−t)² ≥ 0
(a−t)² ≥ 0
taking square root of both sides, we have
√(a−t)² ≥ √0
(a−t) ≥ 0
a ≥ t ⇒ t ≤ a
So, for the particle to move to the right, 0 ≤ t ≤ a.
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