A researcher is interested in estimating the average salary of police officers in a large city. She wants to be 95% sure that her estimate is correct. If the standard deviation is $1050, how large a sample is needed to get the desired information and to be accurate within $200?
Z D/2 = 1.96

The sample size is 183.

Step-by-step explanation:

Given:

σ = $1050, ppulatin standard deviation

99% confidence interval

Accuracy = +/- $200

The accuracy is given by

z*(σ/√n)

where

z* = 2.576 for 99% confidence level (from tables)

n = sample size

Therefore

2.576(1050/√n) = 200

√n = (2.576*1050)/200 = 13.524

n = 182.9

The sample size is 183

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Tenth

Step-by-step explanation:

the value of 8 in 0.837 is a tenth