Mathematics: Aball is thrown into the air with an upward velocity of 80ft/s. its height h in feet after t seconds id given by the function h= -16t^2+80t+5. what is the maximum height the ball reaches? how long will it take the ball to reach maximum height? how long does it take for the mall to be caught 5 feet off the ground? all i really need on is the last one.will some one plz me.

Aball is thrown into the air with an upward velocity

Ответ:

iaminu50

14.03.2022

1. The function H= -16T^2+80T+5 is a parabola of the form $a x^{2} +bx+c$ , so to find the maximum height of the ball, we are going to find the y-coordinate of the vertex of the parabola. To find the y-coordinate of the vertex we are going to evaluate the function at the point $\frac{-b}{2a}$ .
From our function we can infer that b=80

and

, so the point \frac{-b}{2a} [/tex] will be $\frac{-80}{-2(16)} = \frac{5}{2}$ . Lets evaluate the function at that point:
h=-16t^2+80t+5

$h=-16( \frac{5}{2} )^2+80( \frac{5}{2} )+5$
h=105

We can conclude that the ball reaches a maximum height of 105 feet.

2. Since we now know that the maximum height the ball reaches is 105 feet, we are going to replace