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marissastewart533
17.07.2019 •
Mathematics
Acircle is centered at the point (5,-4) and passes through the point (-3,2). what is the equation of the circle?
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Ответ:
(x-h)2 + (y-k)2 = r2
where (h,k) is the location of the center and r is the radius. So we need to find h, k, and r. The center is given as (5,-4) so h = 5 and k = -4:
(x-5)2 + (y-(-4))2 = r2
(x-5)2 + (y+4)2 = r2
So we need to find r. Use the distance formula to find the distance between (5,-4) and (-3,2):
r = [(5-(-3))2+((-4)-2)2]1/2
r = [82 + (-6)2]1/2
r = [64 + 36]1/2
r = 1001/2
r= 10
The final equation is:
(x-5)2 + (y+4)2 = 102
Ответ: