Admission to the zoo is $6 for children and $9 for adults. on a certain day, 1480 people go to the zoo and $10,500 is collected.
how many children and adults went to the zoo?

6x+9y = 10500
x+y = 1480
 
Using elimination I get: 6x + 9y = 10500 -6x-6y = -8880
Add the 2 equations and I get 3y = 1620
Divide both sides by 3 and I get y = 540
 Substitute that back in to 6x+9y = 10500.
 I get that 6x+9*540 = 10500 9 * 540 = 4860
 Subtract 4860 from both sides and I get 6x = 5640
 Divide both sides by 6 and I get x = 940
 So there must have be 940 children and 540 adults

The answer would Be C. Or B

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