Aminor league baseball team plays 101 games in a season. if the team won 14 more than twice as many games as they lost, how many wins and loses did the team have?

A minor league plays 101 games,
They win 14 more than twice as many as they lost.
How many wins and loses?

Okay, simple.
First, write a simple addition equation. In this case wins = w and losses = l.
l + w = 101.

Now, we have to figure out a way to make one of the terms the same term as the other, in this case we can change the terms of w to l.
l = l
w = 2l +14 (14 more than twice the amount)

Okay. So plug in the new amount for w.
l + 2l + 14 = 101. Great! we now have a simple equation. lets solve.
put similar terms together.
3l + 14 = 101
3l = 87
l = 29
So, we have 29 loses, and
w = 2(29) + 14
72 wins!
To check,
72 + 29 = 101, correct!

Hope this helps!

Step-by-step explanation:

Answer is 995

I hope it's helpful!!