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1) the diagram shows equilateral triangle abc sharing a side with square abcde. the square has side lengths of 4. what is the length of line be? justify your answer. (in image)

2) *in image*

1) The length of BE ≅ 7.73

2) The beam clear the wires in its way to standing up straight because the length of the wire less than the height of the wires by 0.332

Step-by-step explanation:

Figure 1:

∵ The equilateral Δ share the side of the square

∵ The length of the side of the square = 4

∴ The length of the side of the Δ = 4

In Δ EAB:

∵ AE = 4 and AB = 4

∵ m∠A = 90 + 60 = 150°

By using cos Rule:

∵ (BE)² = (AE)² + (AB)² - 2(AE)(AB)cosA

∴ (BE)² = (4)² + (4)² - 2(4)(4)cos150 = 59.71281

∴ BE = 7.7274 ≅ 7.73

Figure 2:

∵ The beam makes ∠40° with the ground

∵ The top of the beam is above ground by 8 ft

∴ The length of the beam = 8/sin(40) = 12.446

∵ The beam makes ∠60° with the ground

∵ The length of the beam = 12.44579

∴ The height of the top of the beam from the ground

   = 12.44579 × sin(60) = 10.77837

∵ The height between the top of the beam and the wires in this

   position is 2

∴ The height of the wires from the ground = 10.778 + 2 = 12.778

∵ The length of the beam = 12.446

∴ 12.446 < 12.778

∴ The beam clear the wires in its way to standing up straight

I believe the answer would be D.