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nida7864
04.07.2019 •
Mathematics
Astudent scale recorded his weight as 160 lb. his weight is actually 164lb. what is the percent error of the scale
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Ответ:
The percent error of the scale is 2,5%
Step-by-step explanation:
First StepCalculate the difference (error) between the weight recorded and the actual weight in lbs.
difference = 164 - 160
difference = 4 lbs
Second StepConvert the difference into percentage by comparing the difference to the actual weight, then multiplied by 100%
percent of difference =![\dfrac{\text{difference}}{\text{actual weight}} \times 100 \%](/tpl/images/0049/9994/cfe2e.png)
percent of difference =![\dfrac{4}{160} \times 100 \%](/tpl/images/0049/9994/d070a.png)
percent of difference =![\dfrac{400}{160} \%](/tpl/images/0049/9994/f63c3.png)
percent of difference = 2,5%
Ответ:
lets make a common denomiator of 10.
to do that, we will multiple the bottom and the top of 1/5 by 2
1 * 2= 2 5*2 = 10
so now we have 2/10, so
3/10 - 2/10
when you subtract fractions with common denominators, you never subract the denominators,meaning you don't subract the bottoms, only the tops.
so, 3 - 3 = 1
so your answer is 1/10.
Brainliest please!