Can anyone help me in 35_q pls

56105517

Step-by-step explanation:

a. The height of each bar is marked with the number of students it represents. So, the total number of students is the total of the numbers indicating bar height:

  3 + 14 + 21 +12 + 6 = 56

56 students took the exam.

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b. The class interval or class width is the difference between the scores at the edges of the class. Here, the first class has an interval of 60 -50 = 10. All the other classes have the same interval.

The class interval is 10.

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c. The midpoint of a class is the average of the endpoints. For the first class, it is ...

  (50 +60)/2 = 55

The midpoint for the first class is 55.

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d. There are two bars below 70. The numbers at the top of those bars are 3 and 14, so the total number of students that scored below 70 is ...

  3 + 14 = 17

17 students earned a score less than 70.

The value of c is 125



Work Shown:

(5^5)/(5^2) = 5^(5-2) using the rule (a^b)/(a^c) = a^(b-c)
(5^5)/(5^2) = 5^3
(5^5)/(5^2) = 5*5*5
(5^5)/(5^2) = 125

The alternative way to do this is
5^5 = 3125
5^2 = 25
So (5^5)/(5^2) = 3125/25 = 125