Mathematics: Can someone write the ratios for sin x,cos x and tan x

Can someone write the ratios for sin x,cos x and

cadenbukvich9923

10.03.2022

see explanation

Step-by-step explanation:

For the right triangle

sinx = $\frac{opposite}{hypotenuse}$ = $\frac{4\sqrt{5} }{12}$ = $\frac{\sqrt{5} }{3}$

cosx = $\frac{adjacent}{hypotenuse}$ = $\frac{8}{12}$ = $\frac{2}{3}$

tanx = $\frac{opposite}{adjacent}$ = $\frac{4\sqrt{5} }{8}$ = $\frac{\sqrt{5} }{2}$

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infoneetusinghoyg22o

09.04.2021

x+y=7

y = -x + 7

x+y=3

y = -x + 3

these both have slope -1 so are parallel. that's the

answer: last choice

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