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sarahalexa19
21.06.2021 •
Mathematics
Consider a Poisson distribution with μ = 6.
a. Write the appropriate Poisson probability function.
b. Compute f (2).
c. Compute f (1).
d. Compute P(x≥2)
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Ответ:
a)![P(X = x) = \frac{e^{-6}*6^{x}}{(x)!}](/tpl/images/1380/4172/39878.png)
b) f(2) = 0.04462
c) f(1) = 0.01487
d)![P(X \geq 2) = 0.93803](/tpl/images/1380/4172/01fad.png)
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of successes
e = 2.71828 is the Euler number
In this question:
a. Write the appropriate Poisson probability function.
Considering![\mu = 6](/tpl/images/1380/4172/a06d8.png)
b. Compute f (2).
This is P(X = 2). So
So f(2) = 0.04462
c. Compute f (1).
This is P(X = 1). So
So f(1) = 0.01487.
d. Compute P(x≥2)
This is:
In which:
Then
So
Ответ:
if r=3
area of circle= π(3)²
=9π ≠97
the statement is false