Daily give away today's amount is 100

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Ответ:

Blaked

03.06.2022

Mathematics

t1= 1.1475 sec

t2=9.48 sec

Step-by-step explanation:

This question asking for the time when an object reach a specific height. I will explain what the formula stand for to make this easier.

h= height = 174feet

v0= initial velocity = 170 feet/s

t= time

h0= initial height= ground level = 0

The question have predetermined formula for the height, so we should use it instead of formula that involve gravity value.

h= -16 $t^{2}$ +v0t + h0t

174 feet = -16 $t^{2}$ + 170 feet/s x t + 0 x t

-16 $t^{2}$ + 170 feet/s x t - 174 feet = 0

8 $t^{2}$ - 85 feet/s x t + 87 feet = 0

This equation will be hard to solve since its value in fraction, so lets use the quadratic formula

$x= \frac{-b±\sqrt{ b^2-4ac}}{2a}$

$t= \frac{(85)±\sqrt{ -85^2-4(8)(87)}}{2(8)}$

$t= \frac{85±\ 66.64}{16}$

t1= $\frac{85-\ 66.64}{16}$

t1= 1.1475

t2= $\frac{85+\ 66.64}{16}$

t2=9.48

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