Dome prep school is planning to plant sod to cover their combined track and football field.The field is rectangular in the middle, with a width of 160 feet and a length of 360. On the ends the field is semicircular. If sod is sold in pallets that will cover 50 square yards each, about how many pallets are needed to cover the entire field

150 pallets.

Step-by-step explanation:

Given:

Dome prep school is planning to plant sod to cover their combined track and football field.

The field is rectangular in the middle, with a width of 160 feet and a length of 360.

On the ends the field is semicircular.

If sod is sold in pallets that will cover 50 square yards each.

Question asked:

How many pallets are needed to cover the entire field ?

Solution:

First of all we will find area of rectangular shape in the middle then of semicircle...

Length = 360 feet

Breadth = 160 feet

Now, as figure given below, at the end of the field there is a semicircle both sides of breadth, and boundary of breadth is attached to the semicircle the, radius will be half of the breadth:-

Radius =

Total area of two semicircle = 10057.142 square feet (approx)

Combined area of the field = 67657.142 square feet

1 square feet = 0.111 square yard

67657.142 square feet = 67657.142 0.111 = 7517.46 square yard

To calculate number of pallets.

50 square yards = 1 pallets

1 square yards =

7517.46 square yard =

Therefore, about 150 pallets are needed to cover the entire field.

Sample Response: Each base must be treated separately. Since each base is raised to a negative exponent, they should both be in the denominator of the fractions. The simplified form of the expression has 1 in the numerator and r to the 8th power times s to the 5th power in the denominator.