Mathematics: Expand [x+2/x-3] [x-2/x-3]

Expand [x+2/x-3] [x-2/x-3] - id23237043343, minixkevon

Ответ:

namekianball4

30.01.2022

Mathematics

$\dfrac{x^2-4}{x^2-6x+9}$

Step-by-step explanation:

We assume you want to expand ...

$\dfrac{x+2}{x-3}\cdot\dfrac{x-2}{x-3}=\dfrac{(x+2)(x-2)}{(x-3)^2}=\boxed{\dfrac{x^2-4}{x^2-6x+9}}$

_____

In each case, the product of the factors is ...

(x +a)(x +b) = x² +(a+b)x +ab

For the numerator, you have (a, b) = (2, -2).

For the denominator, you have (a, b) = (-3, -3).

0,0(0 оценок)

Ответ:

asmita9876

30.01.2022

Mathematics

$= \frac{ {x}^{2} - 4 }{ {x }^{2}-6x+9 } \\$

Step-by-step explanation:

$\frac{x + 2}{x - 3} \times \frac{x - 2}{x - 3} \\ \frac{(x + 2)(x - 2)}{(x - 3)(x - 3)} \\ \frac{x(x - 2) + 2(x - 2)}{ {(x - 3)}^{2} } \\ \frac{ {x}^{2} - 2x + 2x - 4 }{ {x}^{2} - 6x+9} \\ = \frac{ {x}^{2} - 4 }{ {x }^{2} -6x+9 }$

0,0(0 оценок)

Ответ:

cpcoolestkid4

11.03.2023

Mathematics

150

Step-by-step explanation:

0,0(0 оценок)

Expand [x+2/x-3] [x-2/x-3]

Ответ:

Ответ:

Ответ:

Ask your question to the AI advisor

More tips

Answers on questions: Mathematics

Ask an AI advisor a question