Find the constant of variation k for the direct variation x -1 0 2 5 f(x) 2 0 -4 -10

k = -2

Step-by-step explanation:

x     -1   0   2     5

f(x)  2   0  -4  -10

ƒ(x) = kx

Substitute a pair of values for x and ƒ(x)

-10 = k×5

Divide each side by 5

k = -2

The constant of variation k = -2.

In -2^2 since the negative sign is not in parentheses you would solve it as 2×2=4 and then have the negative sign so it would be -4. With the parentheses you are saying that the term you are squaring is (-2) and two negatives make a positive so it would be (-2)×(-2)= 4.