Mathematics: Find the difference of 3-5

Find the difference of 3-5 - id357629677, hardyca

Ответ:

stressedstudent101

21.10.2021

(x+9)^2+(y-18)^2=6^2

Step-by-step explanation:

We have been given equation of a circle in general form x^2+y^2+18x-36y+369=0 . We are asked to find the equation of the circle in standard form.

We know that equation of a circle in standard form is of format: (x-h)^2+(y-k)^2=r^2 , where (h,k) represents the center of the circle and r represents radius.

We will convert our given equation in standard form by completing the squares as shown below:

x^2+18x+y^2-36y+369-369=0-369

x^2+18x+y^2-36y=-369

Adding $(\frac{b}{2})^2$ to both sides of our equation we will get,

$(\frac{18}{2})^2=(9)^2=81$

$(\frac{36}{2})^2=(18)^2=324$

x^2+18x+81+y^2-36y+324=-369+81+324

x^2+18x+81+y^2-36y+324=36

(x+9)^2+(y-18)^2=6^2

Therefore, the equation of the given circle in standard form would be (x+9)^2+(y-18)^2=6^2 .

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