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ilovecatsomuchlolol
24.06.2019 •
Mathematics
Find three consecutive even integers. such as that 5 times of the first integer is 18 more than the sum of second and third interferes
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Ответ:
The numbers would be 2, 4, and 6.
Step-by-step explanation:
In order to find this, start by setting the lowest number as x. Then we can determine that the next two even integers are x + 2 and x + 4. From this we can write the following equation.
5(x) = x + 2 + x + 4
5x = 2x + 6
3x = 6
x = 2
Since the first number is 2, we know the next two are 4 and 6.
Ответ:
But here's the first 1,000 digits of pi:
3.1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823066470938446095505822317253594081284811174502841027019385211055596446229489549303819644288109756659334461284756482337867831652712019091456485669234603486104543266482133936072602491412737245870066063155881748815209209628292540917153643678925903600113305305488204665213841469519415116094330572703657595919530921861173819326117931051185480744623799627495673518857527248912279381830119491298336733624406566430860213949463952247371907021798609437027705392171762931767523846748184676694051320005681271452635608277857713427577896091736371787214684409012249534301465495853710507922796892589235420199561121290219608640344181598136297747713099605187072113499999983729780499510597317328160963185950244594553469083026425223082533446850352619311881710100031378387528865875332083814206171776691473035982534904287554687311595628638823537875937519577818577805321712268066130019278766111959092164201989
But you probably only need like first two digits (which is most common shorten pi):
3.14