How much grain can this container hold? Use 3.14 to approximate your pi. Round your answer to the nearest hundreth

953.78in^3 of grain

Step-by-step explanation:

You use the equation π r^2 h to find the volume of the cylinder

r =  radius of the base = 9/2

= 4.5 in  and the height h = 15 in

the volume is 3.14 * 4.5^2 * 15

= 953.78 in^3.

625 metres

Step-by-step explanation:

Given the area function expressed as a(w)=-(w-25)^2+625.

The maximum area occurs at when da/dw = 0

da/dw = -2(w-25)

0 = -2(w-25)

-2(w-25) = 0

w - 25  = 0

w = 25

Substitute w = 25 into the modeled equation;

Recall a(w)=-(w-25)^2+625.

a(25)=-(25-25)^2+625

a(25) = 0+625

a(25) = 625

Hence the maximum area possible is 625 metres