I need help with this math homework

9514 1404 393

Step-by-step explanation:

These are two "special triangles." The ratios of side lengths are numbers not difficult to remember. They can save a lot of work in problems like this.

Ratio of side lengths in 45°-45°-90° isosceles right triangle: 1 : 1 : √2.

Ratio of side lengths in 30°-60°-90° right triangle: 1 : √3 : 2.

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The side marked x has the same length as the side marked 14√2.

  x = 14√2

The unmarked hypotenuse of both triangles is √2 times the marked side length, so is (14√2)(√2) = 28.

The side marked y is half the length of the hypotenuse of that triangles so is ...

  y = 28/2

  y = 14

And the side marked z is √3 times the short side of the 30°-60°-90° triangle, so is ...

  z = 14√3

Alternate solution

The mnemonic SOH CAH TOA can help you remember trig relationships. Here, 14√2 is opposite the given 45° angle, and x is adjacent. The trig relation is ...

  Tan = Opposite/Adjacent

  tan(45°) = 14√2/x

  x = 14√2/tan(45°) = 14√2

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To find y or z, we need to know the length of the hypotenuse in the 45° triangle. The given side is opposite the angle, so we can use the sine relation:

  Sin = Opposite/Hypotenuse

  hypotenuse = 14√2/sin(45°) = 28

Now, we can find y and z:

  sin(30°) = y/hypotenuse

  y = (28)sin(30°) = 14

  cos(30°) = z/hypotenuse

  z = (28)cos(30°) = 14√3