Mathematics: Identify the equation of the circle that has its center at (16, 30) and passes through the origin

is the median for both of them .Step-by-step explanation:...

Identify the equation of the circle that has its

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huwoman

27.08.2021

To solve this question, we have to find the equation of the circle with given center and where it passes. Doing this, we get that the equation of the circle is:

(x - 16)^2 + (y - 30)^2 = 1156

Equation of a circle:

The equation of a circle with center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

Center at (16, 30)

This means that x_0 = 16, y_0 = 30

Thus

(x - 16)^2 + (y - 30)^2 = r^2

Passes through the origin:

We use this to find the radius squared, as this means that x = 0, y = 0 is part of the circle. Thus

(x - 16)^2 + (y - 30)^2 = r^2

(0 - 16)^2 + (0 - 30)^2 = r^2

r^2 = 16^2 + 30^2 = 1156

Thus, the equation of the circle is:

(x - 16)^2 + (y - 30)^2 = 1156

For another example to find the equation of a circle, you can look at

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Identify the equation of the circle that has its center at (16, 30) and passes through the origin

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