If 2a+3b=12 and ab=6 find the value of 8a^3+27b^3

A) 2a + 3b = 12
B) ab = 6 solving for a
B) a = 6 / b then we substitute this into equation A)
A) 12 / b + 3b = 12  multiplying this by "b"
A) 12 + 3b^2 = 12b
A) 3b^2 -12b +12= 0 dividing by "3"
A) b^2 -4b + 4 = 0
Factoring
(b-2) * (b-2) = 0
b = 2
Since b = 2 then a = 3

NOW, we put these numbers into:
8a^3 +27b^3
8*3*3*3 + 27*2*2*2
216 + 216
The answer is 512

A b = 6
a = 6/b
2 *6/b + 3b = 12
12/b + 3b = 12
12 + 3b^2 = 12b
3b^2 - 12b + 12 = 0
b^2 - 4b +4 = 0
(b -  2)^2 = 0
b = 2
a will = 3
8*3^3 + 27*2^3
8*27 + 27*8
I'm getting 432

I thought perhaps I could do this a shorter way. Turns out I can't. If you give out a  Please give it to the other responder.

If a number ends with a '0' or with a '5' then it is divisible by 5.

So, 825 is the answer.