If you have 12 different cars and can only place 4 of them into the show case at one time. how many ways could you display them

You could arrange them 3 different ways at once.

Step-by-step explanation:

You have 12 different cars, but only 4 can be shown at once.

Divide 12 by 4, and you'll get 3.

Therefore, if you wanted to show them all at once, you could make 3 different displays.

y = (25+x)(4000-100x)

Step-by-step explanation:

Given,

The original price of each ticket = $ 25,

Let x be the times of $ 1 increment,

So, the new price of each ticket = $ (25+x),

Also, the original number of seats = 4000,

∵  For each $1 increase in ticket price, 100 fewer tickets will be sold,

Thus, the new number of tickets = 4000 - 100x

Since, revenue = price of each tickets × the number of tickets,

Hence, the total amount of money collected,

y = (25+x)(4000-100x)

Which is the required function.