Jay bought 3 dogs that each cost the same. the total cost was 145.71. what was the price was each dog

Ok so all you have to do is divide 145.71 by 3 to get the price of each dog.

145.71 ÷ 3 =

$48.57

Each dog cost $48.57. Hope that helps!

You divide 145.71 by 3. $48.57 would be the cost per dog.

The probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is 0.234375.

Step-by-step explanation:

Using the Minitab software for computing the desired probabilities.

We take n=6 and p=1/2  because we have six tosses and in binomial distribution the probability of success p remains constant in each trial whereas the probability of success in this case is getting heads.

When a coin is tossed then there are two possible outcomes head or tail.

So,

p= P(heads)=1/2=0.5  

The probability of getting zero heads in six tosses is computed by considering the following steps:

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=0 and bubble the probability and by clicking OK we get the following output:

Probability Density Function  

Binomial with n = 6 and p = 0.5

x  P( X = x )

0    0.015625

So, the probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is computed by considering the following steps :

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=2 and bubble the probability and by clicking OK we get the following output:

Probability Density Function  

Binomial with n = 6 and p = 0.5

x  P( X = x )

2    0.234375

So, the probability of getting exactly two heads in six tosses is 0.234375.