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RoyalGurl01
09.11.2020 •
Mathematics
Mrs. Hernandez was helping her students with their bank accounts. The ratio of the amount of the student with the most money to the student with the least money was 4:1. If the student with the most money has $128, how much does the student with the least money have
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Ответ:
$32
Step-by-step explanation:
From the information given in the question, we are told that the ratio of the amount of the student with the most money to the student with the least money was 4:1. If the student with the most money has $128.
This shows that the student with most money has quadruple that is 4× the student with the least money. Therefore, the student will least money will have:
= $128/4
= $32
Ответ:
(A)
Step-by-step explanation:
The given trigonometric ratio is :
On solving this, we get
=![sin240^{{\circ}}](/tpl/images/0501/4860/5df58.png)
=![sin(180+60)](/tpl/images/0501/4860/475ba.png)
=![-sin60^{{\circ}}](/tpl/images/0501/4860/2a1ea.png)
=![-\frac{\sqrt{3}}{2}](/tpl/images/0501/4860/f6018.png)
(A) The given trigonometric ratio is :
=![cos150^{{\circ}}](/tpl/images/0501/4860/46c00.png)
=![cos(180-30)](/tpl/images/0501/4860/2771e.png)
=![-cos30^{{\circ}}](/tpl/images/0501/4860/bd6e7.png)
=![-\frac{\sqrt{3}}{2}](/tpl/images/0501/4860/f6018.png)
Which is equivalent to the given trigonometric ratio, thus (A) is correct.
(B) The given trigonometric ratio is :
=![cos300^{{\circ}}](/tpl/images/0501/4860/b285c.png)
=![cos(360-60)](/tpl/images/0501/4860/5e995.png)
=![-cos60^{{\circ}}](/tpl/images/0501/4860/7b238.png)
=![-\frac{1}{2}](/tpl/images/0501/4860/3e56c.png)
which is not equivalent to the given trigonometric ratio, thus(B) is incorrect.
(C) The given trigonometric ratio is :
=![\frac{\sqrt{3}}{2}](/tpl/images/0501/4860/5848d.png)
which is not equivalent to the given trigonometric ratio, thus(C) is incorrect.
(D) The given trigonometric ratio is :
=![sin210^{{\circ}}](/tpl/images/0501/4860/d7c1d.png)
=![sin(180+30)](/tpl/images/0501/4860/5a3b0.png)
=![-sin30^{{\circ}}](/tpl/images/0501/4860/6b260.png)
=![-\frac{1}{2}](/tpl/images/0501/4860/3e56c.png)
which is not equivalent to the given trigonometric ratio, thus(D) is incorrect.