Mathematics: One group (A) contains 720 people. One-fifth of the people in group A will be selected to win $15 fuel cards. There is another group (B) in a nearby town that will receive the same number of fuel cards, but there are 659 people in that group. What will be the ratio of nonwinners in group A to nonwinners in group B after the selections are made? Express your ratio as a fraction or with a colon.

80=x+4x80=5xx=16The two parts are 16 and 64...

One group (A) contains 720 people. One-fifth

davidgarcia522083

19.01.2022

The ratio of non-winners in group A to non-winners in group B is

576 : 515.

Step-by-step explanation:

It is provided that, in group A, of the 720 people $\frac{1}{5}$ of the people will win $15 fuel cards.

The number of people winning the cards is:

$n(Win\ cards)=n(A) = 720\times\frac{1}{5} =144$

Then the number of people not winning cards in group A is:

$n(A^{c})=720-n(A)=720-144=576$

Also the same number of people win the cards in group B of 659 people.

Compute the number of people not winning cards in group B as follows:

$n(B^{c})=659-144=515$

Compute the ratio of non-winners in group A to non-winners in group B as follows:

$n(A^{c}):n(B^{c})=\frac{576}{515}$

Thus, the ratio of non-winners in group A to non-winners in group B is

576 : 515.

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