Please help me out with these trig problems

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JonJon05

17.11.2021

Mathematics

5) x = 0.75

6) x = 12

Step-by-step explanation:

Use geometric mean of altitude

$12 = \sqrt{x^2 * 16^2} \\12^2 = x^2 * 16^2\\144 = 256x^2\\x = 0.75$

Use geometric mean of legs

$60^2 = \sqrt{(36+x)^2+36^2} \\3600 = (36+x)^2 + 36^2\\x=12$

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