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issacbeecherpebpyl
19.09.2020 •
Mathematics
Simply. Helppppppppp pleaseee
P² 2p 1
————— - ————— + —————
(y-p)^y. (y-p)^y-1. (y-p)^y-2
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Ответ:
(2p(p - y - 1) + y^2)) / (y - p)^y.
Step-by-step explanation:
p^2 / (y - p)^y - 2p / (y - p)^y + 1 / (y - p)^y-2
The LCD is (y - p)^y
NOTE : (y - p)^y / (y - p)^y-2 = (y - p)^(y - (y - 2)) = (y - p)^2
So we have
(p^2 - 2p + 1( (y - p)^2) / (y - p)^y
= ( p^2 - 2p +y^2 - 2py + p^2) / (y - p)^2
= (2p^2 - 2py - 2p + y^2) / (y - p)^y
= (2p(p - y - 1) + y^2)) / (y - p)^y.
Ответ:
The picture is the answer tell me if you need help!
Hope this helps and have a great day!!
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