Solve the system of equations using the addition method 2a+3b=-1 ; 3a+5b=-2

Then, a=-1 and b=-1

Step-by-step explanation:

We need to solve the following system of equations using the adition method:

2a+3b=-1       (i)

3a+5b=-2      (ii)

First, we multiply the equation (i) by -3 and the equation (ii) by 2, so we get:

-6a-9b=3

6a+10b=-4

Adding the two equations we have:

-6a-9b=3

6a+10b=-4

 0  + b = -1

Then b=-1. Now, let's substitute the value of b into equation (i):

2a+3b=-1

2a + 3(-1) = -1

2a -3 = -1

2a = 2

a = 1

Then, a=-1 and b=-1

a = 1 and b= -1

Step-by-step explanation:

It is given two equations,

2a + 3b = -1  and

3a + 5b = -2  

To find the solution of given equations

Let, 2a + 3b = -1   (1)

3a + 5b = -2   (2)

(1) * -3 ⇒

-6a - 9b = 3    (3)

(2) * 2 ⇒

6a + 10b = -4   (4)

(3) + (4 )⇒

-6a - 9b = 3    (3)

6a + 10b = -4   (4)

  0 + b  = -1

(1) ⇒ 2a + 3b = -1  

2a + (3 * -1) = -1

2a = -1 + 3 = 2

a = 2/2 =1

Therefore, a = 1 and b = -1

Let us check plugging in the values x=-2 y=-6
-6<-14+8
-6<-6
which is false so no it is not in the solution set
actually the soultion set of this function will be the area under the line if it was to be graphed and since this point is on the line it is not part of the soultion