Solve this please with an explanation of process your finding the values of x and y

Congruent sides, so isosceles triangle.  When we have an isosceles triangle the bisector of angle A is a perpendicular bisector of BC with foot D.   So x=ADB=90 degrees.

Angle B is 47 degrees and angle y=BAD is complementary, the other acute angle in a right triangle.

y = 90 - 47 = 43

x=90, y=43

x =90

Step-by-step explanation:

Cot 1/2x-1=0

Add 1 to both sides

Cot 1/2x = 0+1

Cot 1/2x = 1

1/tan1/2x = 1

Tan 1/2x = 1

1/2x = arctan1

1/2x =45

x = 45×2

x = 90

Hence the value of x is 90