The length of a classroom is 4 feet longer that’ll it’s width. write a polynomial to express the area of classroom. then calculate the area if the width is 22 feet.

 Expression for the area of the classroom → (w² + 4w) square feet

 Area of the classroom having width 22 feet → 573 feet

Let the length of the classroom = l feet

And width of the classroom = w feet

Statement given in the question is,

 "Length of a classroom is 4 feet longer than its width"

Algebraic expression for the given statement by using variables 'l' and 'w' will be,

l = w + 4

Since, area of a rectangle is given by the expression,

Area = Length × width

Area of the classroom will be,

Area = l × w

        = (w + 4) × w [Since, l = (w + 4)]

        = w² + 4w

If the width is 22 feet, area of the classroom will be,

Area = w² + 4w

        = (22)² + 4(22)   [By substitution method]

        = 572 square feet

   Therefore, expression for the area of the classroom will be (w² + 4w) square feet and for the width measuring 22 feet, area of the classroom will be 573 feet².

Learn more about the Algebraic equations for the statements here,

link

Polynomial: A = x(x+4)

A = 572 ft^2

Step-by-step explanation:

The polynomial is just x, the width, multiplied by x+4, the length.

The area is just A = 22(22+4). This equals 572 ft^2

7/8

Step-by-step explanation:

Odds against are the ratio between losses and wins.

odds against = L / W

Probability of winning is the ratio between wins and all games.

probability = W / games

probability = W / (W + L)

The odds against are 1 to 7.

1/7 = L / W

W = 7 L

The probability is therefore:

P = (7 L) / (7 L + L)

P = 7/8