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djgunderson
27.10.2020 •
Mathematics
the prices of stock A at 9am was $12.18 since then the price has been increasing at the rate of $0.06 each hour. At noon the price of stock B was $12.68. It begins to descrease at the rate of $0.09 per hour. If the 2 rates continue in how many hours will the prices of the two stocks be the same?
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Ответ:
3.33hours
Step-by-step explanation:
Where the number of hours = h
the prices of stock A at 9am was $12.18 since then the price has been increasing at the rate of $0.06 each hour.
The Algebraic expression =
$12.18 + $0.06 × h
12.18 + 0.06h
At noon the price of stock B was $12.68. It begins to descrease at the rate of $0.09 per hour.
$12.68 - $0.09×h
12.68 - 0.09h
If the 2 rates continue in how many hours will the prices of the two stocks be the same?
Stock A = Stock B
12.18 + 0.06h = 12.68 - 0.09h
Collect like terms
0.06h + 0.09h = 12.68 - 12.18
0.15h = 0.5
h = 0.5/0.15
h = 3.3333333333 hours
h = 3.33hours
Ответ: